# The Greenhouse Equation

This is an account of the **Greenhouse Equation**,
as described on page 49 in chapter 5 of *A Farewell
to Ice* by Peter Wadhams.

Consider a black body at temperature $T$. Temperature is measured
in degrees Kelvin (K). A black body is a perfect emitter and absorber of radiant
energy (heat, light, microwaves, etc). The rate at which energy is
emitted at all wavelengths by such a body per square meter is called its
*radiant flux*. The radiant flux increases with temperature (think of
hot coals: dull red if not too hot, much brighter/whiter if you blow on them).
The precise dependence of radiant flux on temperatue is given by the
Stefan-Boltzmann law (1855): radiant flux is $\sigma T^4$, where
the constant $\sigma$ is about $5.67 x 10^{-8}$ watts per square meter per degree K to
the fourth power.

Let $\epsilon$ be the *emissivity* of a real body. This is a q
between 0 and 1 that describes the deviation from the “ideal”
condition of a black body. As we discuss below, the Earth with
no atmosphere is very nearly a black body: $\epsilon = 1$.
An atmosphere reduces the emissivity ($\epsilon < 1$), with the
precise value depending upon the nature of the atmosphere, e.g., the
mixture of gases that it contains.

The amount of energy emitted by body per unit time is its radiant flux multiplied by its surface area. Energy per unit time has the units of power, measured in watts. The radiant energy per unit time emitted by a spherical body of radius $R$ is therefore

$$ E_{emitted} = 4 \pi R^2 \epsilon \sigma T^{4} $$

In our case, $R$ = radius of the Earth.

The solar flux (incoming energy) at the radius of the Earth’s
orbit is $S = 1.37$ kilowatts per square meter.
We now ask: how much of that incoming energy is absorbed by the
Earth? We know that certain fraction is reflected back into space,
while the rest is absorbed. Let $\alpha$ be the fraction of
the energy whih is reflected. This is called the *albedo*. As a point of reference,
the albedo of fresh snow is about $0.9$, while the albedo of open sea water
is about $0.1$. The albedo of the Earth as a whole epends on cloud cover, the extent of the polar
ice caps, etc., but is presently about $0.3$.

We can calculate the amount of energy absorbed by the Earth per unit time:

$$ E_{absorbed} = \pi R^2 S (1 - \alpha) $$

In the steady state,the incoming and outgoing flows of energy — the absobed and emitted quantities — are in balance. Setting these quantities equal to eachother and solving the resulting equation, one finds that

$$ T^4 = \frac{1}{4\sigma} \frac{S(1 - \alpha)}{\epsilon} \quad\quad (\text{Greenhouse Equation}) $$

Let’s unpack the Greenhouse Equation. First, note that that the $R$’s cancel out. Next, note that the factor $1/4\sigma$ is a physical constant. There remain three variables $S$, $\alpha$, and $\epsilon$ -— solar flux, albedo, and emissivity. These three variables determine the equilibrium temperature of the Earth.

Let’s first study the effect of changing emissivity and albedo.

## Exercise 1: assume no atmosphere

As a first exercise, suppose that $\alpha = 0.3$ and $\epsilon = 1$. That is we take the albedo of the Earth to be about what it is now, with regions of land, sea, and ice, but we assume that the Earth has no atmosphere, and so acts as a black body. Solving for the temperature under these conditions yields

$$ T = 255\ K $$

This works out to about $-18$ degrees C. The Earth without an atmosphere, with an emissitivy of 1, would be very cold – too cold to support life. Atmosphere is more than a medium in which birds fly and which supplies us with the oxygen that powers our cells.

Let’s continue playing with emissivity.

## Exercise 2: Add $\text{CO}_2$.

Adding $\text{CO}_2$ to the atomosphere lowers the emissivity of the Earth. Why? Because $\text{CO}_2$ molecules absorb infrared radiation, converting it into random molecular motion, i.e., heat. The energy of the infrared radiation that would normally be carried back into space is instead trapped in the atmosphere. Q.E.D. What is the effect? Since $\epsilon$ appears in the denominator of the Greenhouse Equation, the equilibrium temperature rises as the emissivity decreases.

## Exercise 3: Melt the north polar ice cap.

If we melt the north polar ice cap, we decrease the albedo of the Earth. That is, we decrease $\alpha$, and therefore increase $1 - \alpha$. Conclusion: the equilibrium temperature increases.

## Exercise 4: Change the behavior of the sun.

The solar flux $S$ is not constant: there is, for example, the well-known 11-year solar cycle, the “sun-spot cycle,” with an associated cycle in energy flux (see reference [3]). The relative increase in $S$ from valley to peak is about 0.002, or 0.2%. However, because the cycle is a periodic — or almost periodic — phenomenon, its long-term effect is very small, likely zero: increases in solar flux in one half of the cycle are balanced by decreases in the other half.

Not well understood, though much discussed, are longer period cycles and long term drift in $S$, if any. Good data is hard to come by: the best measurements are of recent origin, from space-based instruments. An interesting but speculative approach is to study sun-like stars.

## Comments

We, the human race, have had an effect on emissivitiy by adding $\text{CO}_2$ to the atmosphere. The resulting heating has reduced ice cover than therefore has indirectly reduced albedo. Human activity can affect emissivity and albedo, but not the solar flux.

Sadly, as we see with albedo, most of the climate feedback loops are positive, rather than negative. Negative feedback, of which a thermostat is an example, is a Good Thing. Systems with negative feedback are stable. Positive feedback is a Bad Thing in this context. Systems with positive feedback are unstable. Read

*runaway*and imagine a mis-wired thermostat that increases the fuel fed to the furnace as the temperatue rises.

## Note

The Kelvin scale of temperature is related to Centigrade by the equation $T_C = T_K - 273.16$. That is water freezes at 273.16 degrees K. Seems like an odd scale. But: absolute zero, or 0 degrees K, is the temperature at which all molecular motion ceases (well, up to a small quantum effect). Absolutel zero is also the temperature at which an ideal gas occupis zero volume.

## References

A Farewell to Ice, by Peter Wadhams

Solar Cycle Varation in Solar Irradiance, by K.L. Yeo·N.A. Krivova·S.K. Solanki.